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The square pyramid is one of the five basic geometries from which molecular shapes are determined.

A) True
B) False

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Which of these elements is capable of forming the strongest π\pi -bonds?


A) Hydrogen
B) Helium
C) Lithium
D) Carbon
E) Germanium

F) C) and D)
G) A) and E)

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An energy level scheme for the orbitals of second row diatomic molecules O2 through Ne2 , lists the molecular orbitals in the following order of increasing energy σ\sigma 2s < σ\sigma *2s < σ\sigma 2p(z) < π\pi 2p(y) , π\pi 2p(x) < π\pi *2p(y) , π\pi *2p(x) < σ\sigma *2p(z) Based on this energy level scheme, how many electrons are there in all of the antibonding molecular orbitals of the F2+ ion in its ground state?


A) 1
B) 2
C) 3
D) 4
E) 5

F) D) and E)
G) C) and E)

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E

Based on valence bond theory, the predicted bond angle in the H2S molecule is ________.

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Application of the concepts of VSEPR theory leads to the prediction that the shape of the XeOF4 molecule is


A) bent.
B) linear.
C) regular tetrahedral.
D) triangular planar.
E) square pyramidal.

F) A) and B)
G) C) and D)

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One way to make graphene is to heat silicon carbide, SiC, causing the more volatile elemental carbon to undergo sublimation, after which it is collected and purified.

A) True
B) False

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False

The hexagonal pyramid is one of the five basic geometries from which molecular shapes are determined.

A) True
B) False

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According to valence bond theory, the BrF3 molecule has sp2 hybrid orbitals on the bromine atom.Hint: Consider the valence electrons on the central atom.

A) True
B) False

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Which of these examples is not one of the five basic geometries for molecules and ions?


A) planar triangular
B) octahedral
C) tetrahedral
D) square planar
E) trigonal bipyramidal

F) D) and E)
G) A) and B)

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Which molecule or ion uses an sp2 set of hybrid orbitals on the central atom for ?bonding?Hint: Consider formal charge when deciding on the correct structure and remember that sulfur atoms can access d-orbitals.


A) CS2
B) N2O
C) SO2
D) NF3
E) I3-

F) D) and E)
G) A) and D)

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The PCl3 molecule has hybrid orbitals centered on the phosphorus atom. What are the hybrid orbitals used by the phosphorus atom?

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Which statement about the ammonia molecule, NH3, is true?


A) The N-H bonds are polar, but the molecule is nonpolar.
B) The molecule has both three ?- and one ?-bond.
C) The nitrogen atom utilizes sp3 hybrid orbitals for ?bonding.
D) The H-N-H bond angles are greater than 109.5 degrees.
E) The molecular geometry is planar triangular.

F) B) and C)
G) A) and E)

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The H2 ion, according to MO theory, has a bond order of


A) 0
B) 0.5
C) 1.0
D) 1.5
E) 2.0

F) A) and D)
G) A) and C)

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Electrons in a single, double, or triple bond, count as one, two, and three separate electron domains, respectively.

A) True
B) False

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False

If we use the same molecular orbital energy level scheme for the valence orbitals in the NO molecule as was used for diatomic O2 through N2 molecules, σ2s < σ*2s < σ2p(z)< π2p(y), π2p(x) < π*2p(y), π*2p(x)< σ*2p(z) what is the bond order of the NO molecule?

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Based on the Lewis structure, the number of electron domains in the valence shell of the arsenic atom in the AsCl3 molecule is


A) 1.
B) 2.
C) 3.
D) 4.
E) 5.

F) A) and E)
G) C) and D)

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Based on application of the VSEPR theory, the expected bond angles in the AsF4 ion should be approximately


A) 90 degrees.
B) 109.5 degrees.
C) 120 degrees.
D) 90, 120 and 180 degrees.
E) 90 and 180 degrees.

F) B) and C)
G) B) and E)

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All of the atoms in the nitrate ion lie in the same plane.

A) True
B) False

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A molecule has a central atom surrounded by 2 lone pairs and 3 atoms. The best description for the shape of the molecule is


A) trigonal bipyramidal.
B) octahedral.
C) trigonal planar.
D) T-shaped.
E) see-saw.

F) B) and C)
G) C) and E)

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In the CSe2 molecule,


A) the bonds are all nonpolar, which makes it polar.
B) the bonds are polar, but their effect on the overall polarity is canceled by the effect of lone pairs in the valence shell of the carbon atom.
C) the bonds are polar, but their effect on the overall polarity is canceled by the fact that they are equal in magnitude and oppositely directed.
D) the bonds are polar, but the polar effect is canceled by the resonance hybrids which distribute the charge evenly.
E) the bonds are slightly polar, and so they will not affect the overall polarity of the molecule.

F) A) and B)
G) D) and E)

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